Notes

T2T1=(rpc)(?-1)?.nc rpg=1-?11-?2(rpc) f=cpgt3-cpat2cv-cpa t2 afr=(1-f)f exca=(afr-17.24)17.24 t4=t3(rpg)(?-1)nt? ws=cpg(t4-t5)(ha-hf) t6=t4-ws(ha-he)cpg xbs=(sa-0.1059)8,869 hbs=29.30+2484.9(xbs) wst=ms(ha-hbs)ntst mg=(ms/ws); wa=(1-f)mg; wgt= mgcpg(t3-t4)- wacpa(t2-t1) wnet= wst + wgt; wf= f.mg; // mass flow tell of fuel nst=(ha-hbs)ntst(ha-he)ntst no=wnetwf.cv ntgt=wgtwf.cv xl=mg.cpg(t6-t1)wf.cv no1=nst+ntgt-nst.ntgt-(ntgt.xl) ra=cpa(?-1)? ic=wat1[cpalog?(rpc)?-1?.nc-ra.logrpc] rg=cpg.(n-1)n igt=mg.t1[cpg.log1rpgn-1ntn-rg.log(1rpg)] se=2.046 se=2.

046; // constant ihrsg= t1* ((ms*(sa-se)) + (mg*((cpg*log((t6/t4)))-(rg*log(1/(1+b2)))))); // Steam Turbine hb= ha - (ntst*(ha-hbs)); xb=(hb-29.30)/2484.9; sb=0.1059+ (xb*8.869); ist=ms*(sb-sa)*t1; // irritate loss iexh= mg*cpg*((t6-t1)-(t1*log((t6/t1)))); // combustor sp3=mg*cpg*log((t3/t1))-mg*rg*log((rpc*(1-b1))); sr2=mg*cpg*(log(pow(rpc,pow1)))-wa*ra*log(rpc); //p,r,a & f represent product,reactant, air,fuel //for ch4 sy=1.0401+(0.1729*4*1)/(1*12); ho=wf*cv; go=sy*ho; so=go-ho; icomb= t1*(sp3-sr2)+so;If you deficiency to get a measure essay, order it on our website: Ordercustompaper.com

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